Concept : numbers of consecutive natural numbers sum to n = (number of odd factors of n ) -1
1000 = 5^3 * 2^3here number of odd factors = 4 and required answer = 4 - 1 = 3

The clock loses 30 minutes per hour.
i.e 30 minutes of this faulty clock = 60 minutes of the correct clock
From 2 p.m to 6 p.m ,
total number of hours = 4 hours
4 hours of this faulty clock => 4 x 60/30= 8 hours of original clock
So, The correct time when the clock show 6 p.m = 6 p.m + 4 = 10 p.m
But The clock stopped 3 hours ago ,
So present time is 10 p.m + 3 hours = 1 a.m

Q100) A and B play a game of dice between them. The dice consist of colors on their faces (instead of numbers). When the dice are thrown, A wins if both show the same color; otherwise B wins. One dice has 4 red face and 2 blue faces. How many red and blue faces should the other dice have for both the to players have same chances of winning?
a) 3 red and 3 blue faces
b) 2 red and remaining blue
c) 6 red and 0 blue
d) 4 red and remaining blue