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    Rowdy Rathore

    @Rowdy Rathore

    Main nahi darta math se, math darti hai mujshe.

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    Topics created by Rowdy Rathore

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      Question Bank - Number Theory
      Quant - Boosters • • Rowdy Rathore  

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      Approach: Numbers having 1/0 in them will not satisfya! * b! > a! + b! as 1 * something is always less than 1 + something.So eliminate numbers having 1/0 in them11-91, 10-90, 12-19= 26 numbersAlso, an exception is 22 where 2! + 2! = 2! * 2!Hence, total 27 numbers will not satisfy. So, 90-27=63 numbers will satisfy [solved by vinit sanghvi]
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      CAT Question Bank - Time & Work
      Quant - Boosters • • Rowdy Rathore  

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      Can you please share the solution?
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      CAT Question Bank - Arithmetic
      Quant - Boosters • • Rowdy Rathore  

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      Q30) P and Q run on a circular track of 100m. Speed of P is 250 m/s and that of Q is 400 m/s. In how many points on a circular track will they meet if they start simultaneously from the same point, in the same direction?
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      CAT Question Bank - Co Primes
      Quant - Boosters • • Rowdy Rathore  

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      If N = p1^a + p2^b + p3^cthen ordered factor pairs coprime to each other = (2a + 1)(2b + 1)(2c + 1)Unordered factor pairs coprime to each other = {[(2a + 1)(2b + 1)(2c + 1) - 1]/2} + 1 (for (1,1) 360 = 2^3 * 3^2 * 5Ordered factor pairs coprime to each other = (2 * 3 + 1) * (2 * 2 + 1) (2 * 1 + 1) = 7 * 5 * 3 = 105Un ordered factor pairs coprime to each other = (105 - 1)/2 = 52 + 1 = 53if we don't consider (1,1) then 52.Confused! Detailed approach (Hemanth Venkatesh) On factorizing 360 we get the following factors:360 = (2^3) * (3^2) * (5)First suppose that 5 divides neither co prime factor. Then we have two cases:Case 1: One factor must be 2 to some positive power while the other factor must be 3 to some positive power. Hence there are 3 * 2 = 6 of these (as there are 3 possible positive powers of 2 and there are 2 possible positive powers of 3).Case 2: One factor is 1 while the other factor is a divisor of (2^3) * (3^2).Hence there are (3+1)(2+1)=12 of these. Now, note that all of these pairs consist of different numbers except the pair {1,1}. For each of the pairs with two distinct elements, we can multiply either element by 5 to get two new co prime pairs of factors (that is the solution {a,b} gives rise to the solutions {5a,b} and {a,5b}.Finally, the pair {1,1} under this process only gives us one new pair: {1,5}.In conclusion, we have 3(6 + 12 − 1) + 2 = 53 co prime pairs.
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      CAT Question Bank - Binomial Theorem
      Quant - Boosters • question bank binomial theorem • • Rowdy Rathore  

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      General term - nCr * (x^2)^(n-r) (3y)^r It is given that 2n - 2r + r = 52n - r = 5n = 4 => r = 3 So the term we have here is 4C3 * (x^2)^1 (3y)^3Coefficient = 4C3 * 3^3 = 4 * 27 = 108
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      CAT Question Bank - Ordered & Unordered Solutions
      Quant - Boosters • question bank • • Rowdy Rathore  

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      @rowdy-rathore 22
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      CAT Question Bank - Cubes and Cuboids
      Quant - Boosters • question bank • • Rowdy Rathore  

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      @Rowdy-Rathore solution is 32
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      CAT Question Bank - Escalators (Time, Speed & Distance)
      Quant - Boosters • question bank time speed & distance • • Rowdy Rathore  

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      @Rowdy-Rathore 33.6 seconds.
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      CAT Question Bank - Time, Speed & Distance
      Quant - Boosters • question bank time speed & distance • • Rowdy Rathore  

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      @Rowdy-Rathore The speed of the jogger is 15 Km/h
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      CAT Question Bank - Geometry (Area)
      Quant - Boosters • question bank • • Rowdy Rathore  

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      CAT Question Bank - Maxima & Minima
      Quant - Boosters • question bank maxima & minima • • Rowdy Rathore  

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      @Rowdy-Rathore (26/3)^(1/8)
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      CAT Question Bank - Probability
      Quant - Boosters • question bank probability • • Rowdy Rathore  

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      @rowdy-rathore - Solution pls.
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      CAT Question Bank - Functions
      Quant - Boosters • question bank functions • • Rowdy Rathore  

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      @Rowdy-Rathore F(x) = x^4-360x^2+400F(x) = (x^2+20)^2 - 400x^2F(x) = (x^2-20x+20)(x^2+20x+20) = Prime NumberSince the value of second factor is always positive and greater than 1 therefore, 1st factor hasto be equals to 1.x^2-20x+20 = 1x^2-20x+19= 0On solving,x = 1, 19.Putting back the values in the original equation we get f(x) = 41 and f(x) = 761. So, the sum will be 41+761 = 802
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      CAT Question Bank - Games & Tournaments
      DILR - Booster • question bank games & tournaments • • Rowdy Rathore  

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      @Rowdy-Rathore please give the solution
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      CAT Question Bank - Area Of The Region Bounded By Curves (Modulus function)
      Quant - Boosters • question bank • • Rowdy Rathore  

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      Graph is as below: Parallelogram with base = 6 and height = 12Area = bh = 6 x 12 = 72