LET the remaining areas in cyclic order from left be e,a, d, b.and the shaded area be c.
a+b+c =1/2(a+b+c+d+e+97)a+b+c = d+e+97ord+e+97 = a+b+c -------(1)
e+c+d = 1/2(a+b+c+d+e+97)=>e+c+d= a+b+97 ------(2)
subtract (2) from (1)
c-97 = 97-c=>c=97
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