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    Raman Sharma

    @Raman_Sharma

    Faculty and Content Developer at TathaGat
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    • Quant Boosters - Geometry - Raman Sharma - Set 2
      Quant - Boosters • • Raman_Sharma  

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      @Raman_Sharma What is the solution for this?

    • Quant Boosters - Geometry - Raman Sharma - Set 1
      Quant - Boosters • question bank • • Raman_Sharma  

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      @raman_sharma BC =1 , CA =2 so AB =rt5using similarity in triangle ABC and ADCwe get CD= 2/rt5 and diameter of circle as 4/rt5 now using tangent secant theoremCD^2 = CE * AC4/5 = CE *2CE =0.4so AE=1.6hence 1.6/0.4 = 4