@gaurav_sharma answer option:a

@gaurav_sharma 5,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

Let us number the vertices from 1 – 6, there are three different types of triangles that can be formed.Type 1 : (1, 2, 3) [ this is same as (2, 3, 4), (3, 4, 5) … etc)Type 2 : (1, 2, 4) [ this is same as (1, 2, 5) (2, 3, 5) (3, 4, 6)]Type 3 : (1, 3, 5) and (2, 4, 6) have same shape and area So there will be three triangles of different areas that can be formed from a regular hexagon.There are 6 triangles of Type 1, 12 of type 2 and 2 of type 3.Adding these we get 6 + 12 + = 20 triangles. Total number of triangles possible = 6C3 = 20

S = 1 + 4x + 7x^2 + 10x^3 + … Sx = x + 4x^2 + 7x^3 + 10x^4 + … S (1 – x) = 1 + 3x + 3x^2 + 3x^3 + … S (1 – x) = 1 + 3x/( 1 – x) 35/16(1 – x) = (1 – x + 3x) / ( 1 – x) = ( 1 + 2x ) / ( 1 – x) 35 (1 – x) ^2 = 16 (1 + 2x ) 35x^2 – 102x + 19 = 0 (7x – 19) (5x – 1) = 0 x = 19/7, 1/5 But x # 19/7 (because 19/7 > 1) So x = 1/5

(x+y)/xy = 1/x + 1/y Only (1,1) and (2,2) satisfy the equation Hence option C is correct.

@gaurav_sharma 3hour ans ??

@gaurav_sharma said in Quant Boosters - Gaurav Sharma - Set 5: Q26) John and David work on alternate days with John starting on the first day. John does 12.5% of the total work on the last day and finishes the work. If John alone can do the work in 6 days then which of following can be the number of days in which David alone can do the whole work?(a) 24 days(b) 12 days(c) 8 days(d) 10 days Need solutioninlinemathsinline mathsinlinemaths

@gaurav_sharma is it 0???

OA : required probability is 1