Quant Boosters  Sagar Gupta  Set 1

Q26) The no of positive integers n such that (n^6 + 206) is divisible by (n^2 + 2) is ?

n^6 + 206 = k ( n^2 + 2 )
Rearrange :
n^6 + 8 = k (n^2 + 2)  198
(n^2 + 2 ) ( n^4 + 4  2n^2 ) = k (n^2 + 2 )  198
Divide throughout by n^2 + 2
n^4 + 4  2n^2 = k  [ 198 / n^2 + 2 ]
198 / n^2 + 2 must be an integer
n=1 , n = 2 , n=3 , n=4 , n=8 , n=14 > Hence 6 Values

Q27) X takes 9 and Y takes D days to complete a job working alone. They work on alternate days. If they take exactly the same time irrespective of who starts, how many positive integer values are possible for D ?

2m + 18m/d = 18
m + 9m/d = 9
d = 9m / 9m
m=6 : 54/3 =18
m=8 : 72 / 1 = 72

Q28) Find the sum of all values of x , that satisfy (4x^2 + 15x + 17)/(x^2 + 4x+12) = (5x^2 + 16x+18)/(2x^2 + 5x + 13)

m/n = m+p/n+p
mn + mp = mn + np
m = n
4x^2 + 15x + 17 = x^2 + 4x + 12
3x^2 + 11x + 5 = 0
Sum of roots = 11/3

Q29) The values of the numbers 2^2004 and 5^2004 are written one after another. How many digits are there in all?
(1) 4008
(2) 2003
(3) 2004
(4) None of these

No. of digits = logN + 1 ... here it's 2004(log10) + 1=2005
Or by pattern : 2^1 5^1 = 25 : 2 digits
2^2 5^2 = 425 : 3 digits
2^3 5^3 = 8125 : 4 digits
2^4 5^4 = 16625 : 5 digits
2^5 5^5 = 323125 : 6 digits
..
2^2004 5^2004 : 2005 digits

Q30) How many integer solutions exist for the equation 5x  3y = 140 such that x and y are of opposite signs?
a) 8
b) 9
c) 10
d) 11

5x  3y = 140
x=25 , x=22 , x=19 , x=16 , x=13 , x=10 , x=7 , x=4 , x=1
9 solutions