Quant Boosters  Swetabh Kumar  Set 1

4 values
A=(3,7), B(6,2), C(2,k)
AB^2 = 9+25 = 34
AC^2 = 1+(7k)^2 = k^214k+50
BC^2 = 16+(2k)^2 = k^24k+20
if AB is hyp. 2k^218k+70 = 34
k^29k+18= 0
2 real values here.
if AC is hyp: k^24k+54 = k^214k+50
10k=4 so k=0.4 so one value
if BC is hyp, k^214k+84=k^24k+20 so k=6.4 so one value.
so (2+1+1)= 4 values


@swetabh_kumar
x = 3/2 minimum = 1