Quant Boosters  Shashank Prabhu, CAT 100 Percentiler  Set 2

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Number of Questions  30
Topic  Quant Mixed Bag
Solved ? : Yes
Source : Learningroots forum

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q1) From the first 20 natural numbers how many Arithmetic Progressions of five terms can be formed such that the common difference is a factor of the fifth term?
(a) 16
(b) 22
(c) 25
(d) 26

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Take the common difference and then figure out the number of series that can be formed. As soon as you get the last number of the series, you can easily figure out the number of series that can be formed.
For CD = 1 , 16 such APs
For CD = 2, 6
For CD = 3 , 2
For 4 , 1
Total 25

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q2) If A is the sum of the squares of the first n natural numbers (where n < 100), then for how many values of n will A be divisible by 5?
(a) 40
(b) 60
(c) 59
(d) 39

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Consecutive squares starting from 1 end in: 1, 4, 9, 6, 5, 6, 9, 4, 1, 0
If you take progressive sum.... First number, first two numbers, first 3 numbers and so on, it ends in
1, 5, 4, 0, 5, 1, 0, 4, 5, 5
And the cycle will repeat
6 instances in a group of 10 numbers
But 100 is not included as n < 100
So 6 × 10  1 = 59

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q3) Find the no. of positive integer solution for x, y for 2/x + 3/y = 1/6

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
6(2y+3x)=xy
12y+18x=xy
12y+18xxy=0
12yx(y18)=0
As there is y18 inside the bracket, we create another y18 using the coefficient of y, 12 in this case
12(y18)x(y18)+216=0
(x12)(y18)=216
216=2^3 * 3^3 and so, has 4 * 4=16 factors and so, can be written as the product of two factors in 8 ways. As the number of ordered pairs are being asked, we get the answer to be 16.

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q4) If N is a natural number how many values of N exist, such that N^2 + 24N + 21 has exactly three factors?

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Let the RHS be x^2
n^2 + 24n + 21 = x^2
n^2 + 24n + 144  123 = x^2
(n+12)^12  x^2 = 123
(n+12+x)(n+12x)=123=41* 3 or 123 * 1
n=10 or n=50
So, 2 solutions.

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q5) If ‘bcd’ is a three digit number whose square ends with ‘abcd’, then what is the value of a + b + c + d ?
a. 27
b. 13
c. 16
d. 20

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
bcd = 625
It's kinda theoretical in nature. Squares of numbers ending in 005 end in 025, squares of numbers ending in 025 end in 625 and squares of numbers ending in 625 end in 625.

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q6) In an island ‘Pedhauli’, people use only three symbols A, V and P to write any number.
They write 10 as PAP.
They write 15 as PVA.
They write 27 as PAAA.
What is the decimal equivalent of VPAV?
a. 65
b. 66
c. 67
d. 68

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
They simply use base 3... 10 in base 3 is 101, 15 in base 3 is 120, 27 in base 3 is 1000.. so p=1, v=2, a=0 and vpav becomes 2102 which is equivalent to 65 in decimal.

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q7) 500! + 505! + 510! + 515! is completely divisible by 5^n, where n is a natural number. How many distinct values of n are possible?
a. 120
b. 121
c. 124
d. 125

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
500!(1 + 501 * 502 * 503 * 504 * 505 + 501* 502 *... 510 + 501 * 502 *.. * 515)
Inside bracket 5k+1 form
500! Has 124 5s
So c

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q8) A contractor, intending to finish a work in 150 days, employed 75 men. They worked for 8 hours every day for 90 days and completed 2/7th part of the work. Then the contractor increased the number of men by x and thereafter all the men were made to work for 10 hours every day. If the work was completed just in time, then what is the value of x?
a. 225
b. 150
c. 75
d. None of these

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
75 × 8 × 90 × 5/ 2
x = 150

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q9) Identical black tiles, in the shape of a square of side 3 cm, are placed along the two diagonals of a square shaped floor of side 39 cm. The rest of the floor is covered with identical white tiles of same shape and size. How many white tiles need to be replaced by the black tiles so that the black and the white tiles are in alternate positions in all the rows and columns?

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Small tiles of 3 cm sides and larger floor of 39 cm sides essentially means that it is a 13 * 13 grid. So, if we see the tiles along the diagonals, we get 13 * 21=25 tiles that are black colored. Total number of black colored tiles that are required will be (13^2+1)/2=85. So, additional 60 replacements required.

shashank_prabhu last edited by
CAT 100%iler, 5 times AIR 1, Director  Learningroots, Ex ITC, Pagalguy, TAS
Q10) Of the applicants who passed a certain test, 15 applied to both college X and Y. If 20 % of the applicants who applied to college X and 25% of the applicants who applied to college Y applied to both college X and Y, how many applicants applied only college X or college Y?