Quant Boosters - Shashank Prabhu, CAT 100 Percentiler - Set 2



  • Number of Questions - 30
    Topic - Quant Mixed Bag
    Solved ? : Yes
    Source : Learningroots forum



  • Q1) From the first 20 natural numbers how many Arithmetic Progressions of five terms can be formed such that the common difference is a factor of the fifth term?
    (a) 16
    (b) 22
    (c) 25
    (d) 26



  • Take the common difference and then figure out the number of series that can be formed. As soon as you get the last number of the series, you can easily figure out the number of series that can be formed.
    For CD = 1 , 16 such APs
    For CD = 2, 6
    For CD = 3 , 2
    For 4 , 1
    Total 25



  • Q2) If A is the sum of the squares of the first n natural numbers (where n < 100), then for how many values of n will A be divisible by 5?
    (a) 40
    (b) 60
    (c) 59
    (d) 39



  • Consecutive squares starting from 1 end in: 1, 4, 9, 6, 5, 6, 9, 4, 1, 0
    If you take progressive sum.... First number, first two numbers, first 3 numbers and so on, it ends in
    1, 5, 4, 0, 5, 1, 0, 4, 5, 5
    And the cycle will repeat
    6 instances in a group of 10 numbers
    But 100 is not included as n < 100
    So 6 × 10 - 1 = 59



  • Q3) Find the no. of positive integer solution for x, y for 2/x + 3/y = 1/6



  • 6(2y+3x)=xy
    12y+18x=xy
    12y+18x-xy=0
    12y-x(y-18)=0
    As there is y-18 inside the bracket, we create another y-18 using the coefficient of y, 12 in this case
    12(y-18)-x(y-18)+216=0
    (x-12)(y-18)=216
    216=2^3 * 3^3 and so, has 4 * 4=16 factors and so, can be written as the product of two factors in 8 ways. As the number of ordered pairs are being asked, we get the answer to be 16.



  • Q4) If N is a natural number how many values of N exist, such that N^2 + 24N + 21 has exactly three factors?



  • Let the RHS be x^2
    n^2 + 24n + 21 = x^2
    n^2 + 24n + 144 - 123 = x^2
    (n+12)^12 - x^2 = 123
    (n+12+x)(n+12-x)=123=41* 3 or 123 * 1
    n=10 or n=50
    So, 2 solutions.



  • Q5) If ‘bcd’ is a three digit number whose square ends with ‘abcd’, then what is the value of a + b + c + d ?
    a. 27
    b. 13
    c. 16
    d. 20



  • bcd = 625
    It's kinda theoretical in nature. Squares of numbers ending in 005 end in 025, squares of numbers ending in 025 end in 625 and squares of numbers ending in 625 end in 625.



  • Q6) In an island ‘Pedhauli’, people use only three symbols A, V and P to write any number.
    They write 10 as PAP.
    They write 15 as PVA.
    They write 27 as PAAA.
    What is the decimal equivalent of VPAV?
    a. 65
    b. 66
    c. 67
    d. 68



  • They simply use base 3... 10 in base 3 is 101, 15 in base 3 is 120, 27 in base 3 is 1000.. so p=1, v=2, a=0 and vpav becomes 2102 which is equivalent to 65 in decimal.



  • Q7) 500! + 505! + 510! + 515! is completely divisible by 5^n, where n is a natural number. How many distinct values of n are possible?
    a. 120
    b. 121
    c. 124
    d. 125



  • 500!(1 + 501 * 502 * 503 * 504 * 505 + 501* 502 *... 510 + 501 * 502 *.. * 515)
    Inside bracket 5k+1 form
    500! Has 124 5s
    So c



  • Q8) A contractor, intending to finish a work in 150 days, employed 75 men. They worked for 8 hours every day for 90 days and completed 2/7th part of the work. Then the contractor increased the number of men by x and thereafter all the men were made to work for 10 hours every day. If the work was completed just in time, then what is the value of x?
    a. 225
    b. 150
    c. 75
    d. None of these



  • 75 × 8 × 90 × 5/ 2
    x = 150



  • Q9) Identical black tiles, in the shape of a square of side 3 cm, are placed along the two diagonals of a square shaped floor of side 39 cm. The rest of the floor is covered with identical white tiles of same shape and size. How many white tiles need to be replaced by the black tiles so that the black and the white tiles are in alternate positions in all the rows and columns?



  • Small tiles of 3 cm sides and larger floor of 39 cm sides essentially means that it is a 13 * 13 grid. So, if we see the tiles along the diagonals, we get 13 * 2-1=25 tiles that are black colored. Total number of black colored tiles that are required will be (13^2+1)/2=85. So, additional 60 replacements required.



  • Q10) Of the applicants who passed a certain test, 15 applied to both college X and Y. If 20 % of the applicants who applied to college X and 25% of the applicants who applied to college Y applied to both college X and Y, how many applicants applied only college X or college Y?


Log in to reply