Quant Boosters  Hemant Malhotra  Set 1

hemant_malhotra last edited by hemant_malhotra
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Number of Questions  30
Answer Keys available  Yes
Topic  Quant Mixed Bag
Source  Elite's Grid CAT Preparation Forum

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q1) Sarah intended to multiply a twodigit number and a threedigit number, but she left out the multiplication sign and simply placed the twodigit number to the left of the threedigit number, thereby forming a fivedigit number. This number is exactly nine times the product Sarah should have obtained. What is the sum of the twodigit number and the threedigit number?

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
a is a two digit number and b three digit number, so ab is five digit number.
If a = 12 and b = 123 and we are writing 12123 then we can also write it as 12 x 1000 + 123
so 1000 * a + b = 9 * (a) * b
1000/b + 1/a = 9
so 1000/b will be approx 9 so 1000/9 = 112 (approx value)
so b = 112 and a = 14
so sum = 126

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q2) In a ∆ABC, AD & BE are medians and G is the centroid, ∠AGE = 30° , AD=12cm & BE = 18cm. Find the area of the triangle?

hemant_malhotra last edited by hemant_malhotra
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
∠AGE = 30
G will bisect BE in 2:1 ratio so GE = 4 and in same way AG = 12
so area of AGE = 1/2 * AG * GE * sin30 = 1/2 * 12 * 4 * 1/2 = 12
so area of ABC will be 6 times of area of AGE =12 * 6 = 72
[Note  Median divide triangle into 6 equal areas]

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q3) For prime numbers a and b, a + b = 102 and a > b. What is the least possible value of a  b ?

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Question is not important but approach is important here
Minimum will be when a and b are as close as possible so
a = 51 + m and b = 51  m
where 51 + m and 51  m both are primes
at m = 8, 59 and 43 both are prime so minimum difference will be 16

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q4) At Ram's birthday party, the ratio of people who ate ice cream to people who ate cake was 3 : 2. People who ate both ice cream and cake were included in both categories. If 120 people were at the party, what is the maximum number of people who could have eaten both ice cream and cake?

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Those who ate both will be maximum when all who ate cake also ate icecream
n(A U B) = n(A) + n(B)  n (A intersection B)
so 120 = 3x + 2x  2x
so x = 40
so Those who ate both = 2x = 80

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q5) How many ordered triples (a, b, c) satisfy the below equation where a, b and c are real numbers.
(a^2 − 1)^2 + (b^2 −4)^2 + (c^2 − 9)^2 = 0

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
all values will be equal to zero
a^2  1 = 0 so a = +/ 1
b^2  4 = 0 so b = +/ 4
c^2  9 = 0 so c = +/ 3
so 2 * 2 * 2 = 8

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q6) How many subsets A of {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} have the property that no two elements of A sum to 11

hemant_malhotra last edited by zabeer
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Pairs that makes 11 = (1 ,10), (2 ,9), (3 8), (4 7), (5 6)
we have 5 pairs and out of each pair only one or none can go to subset A
so for each pair we have 3 possibilities.
so number of subsets of A satisfying the condition = 3^5 = 243

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q7) The centroid Of a triangle is at (1, 1) While its orthocentre at (5, 3). The circumcentre of the triangle could be at
a) (1, 3)
b) (8/3, 0)
c) (0, 8/3)
d) (7/3, 1/3)

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Centroid bisect ortho and circum in 2:1 ratio
distance between (1,1) and (5,3) is sqrt(16+16)=sqrt32
so distance between centroid and circum should be sqrt32/2
check by options
sqrt(4 + 4) = sqrt8
so OA = A

hemant_malhotra last edited by hemant_malhotra
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q8) A person travels equal distance at a speed of 3 kmph, 4kmph and 5 kmph and takes 1 hour 34 minutes to complete the journey. Find his average speed for the whole journey
a) 3.83 kmph
b) 4.62 kmph
c) 4 kmph
d) 4.11 kmph

hemant_malhotra last edited by hemant_malhotra
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Basic approach to solve 180/47 = 3.8 approx
Quick approach  Average speed of journey will be equal to HM always (when equal distance with different speeds)
HM < AM
AM = (3 + 4 + 5)/3 = 4
so HM < 4
only 1st option satisfies.

hemant_malhotra last edited by
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q9) Find the range of T = 2Cos^4θ + Sin^2θ + 3
a) [1/2, 5]
b) [2, 3]
c) [31/8, 5]
d) [31/7, 4]

hemant_malhotra last edited by hemant_malhotra
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
OA  C
Method 1 
Change in cos or sin
2cos^4 x + 1  cos^2x + 3
let cos^2x = y
2y^2  y + 4 = T
so dT/dy = 4y  1 = 0
so y = 1/4
so 2/16  1/4 + 4
1/8  1/4 + 4
1  2 + 32/8 = 31/8 min value
and max will be 5 when x = 0Method 2  Exam Condition Approach
max value is 5 at x = 0 so 2 and 4 ruled out
now square of any thing will not be negative so min will be 3 in (worst cases ignoring sin and cos)
so only option possible = C

hemant_malhotra last edited by hemant_malhotra
Director at ElitesGrid  CAT 2017  QA 100 Percentile / CAT 2016  QA : 99.94, LRDI  99.70% / XAT 2017  QA : 99.975
Q10) In the figure given below, if O is the centre of the circle and < BAO = 54 then find < OAD + < OCD
a) 108
b) 126
c) 112
d) 120