# CAT Question Bank - Maxima & Minima

• Q20) If f(x) = min(1 - 3|x|, 2|x| - 1), find the maximum value of f(x).

• Q21) Find the minimum value of (p + q + r)(1/p + 1/q + 1/r) where p, q and r are natural numbers.

• Q22) Let x, y, z be three non-negative integers such that x + y + z = 10. The maximum possible value of xyz + xy + yz + zx is

• Q23) which of the following is the maximum value of f(x) = x / (x^2 - x + 1) ? ( given x is a real number )
a) -1/3
b) 2
c) 1
d) 1/3

• Q24) A function f(x) is defined as f(x) = min{4x + 1, x + 2, -2x + 4}
Then maximum value of f(x) is
a) 2
b) 5/2
c) 8/3
d) 17/6
e) 3

• Q25) A function f(x) is defined for all real values of x as min(–x^2, x – 20, –x – 20).
What is the maximum value of f(x)?
(a) –16
(b) –20
(c) –25
(d) None of these

• Q26) a + b + c = 0
a^2 + b^2 + c^2 = 1
If a, b, c be real numbers, find the maximum possible value of (9abc)^2

• Q27) Find the minimum value of f(x) = (6/x) + x^2

• Q28) Find the maximum and minimum values of 3sinx + 4cosx

• Q29) If the equation 3x + 4y = k has 15 positive integral solutions then find the maximum and minimum values of k

• Q30) If a, b, c, d, e and f are non negative real numbers such that a + b + c + d + e + f = 1, then the maximum value of (ab + bc + cd + de + ef) is

• Funda : If the product of positive numbers is a constant then sum is minimum when all numbers are equal.
here a * b * c = 90
So sum is minimum when a = b = c = (90)^1/3
Now this won't be a natural number solution. So we need place them as close as possible
90 = 3^2 * 5 * 2
90 = 3 * 5 * 6
minimum of a + b + c = 3 + 5 + 6 = 14

• No distinct real roots means D = 0
b^2 = 24a
a = b^2/24
3a + b = b^2/8 + b = (b^2 + 8b)/8
Complete the square, (b^2 + 8b + 16 - 16)/8 = (b + 4)^2/8 - 2
as (b + 4)^2 is always non negative, minimum value is -2 when b = - 4

• @Soumya-Ranjan-Patra Answer is root 2. Explanations below

Method 1 :
Let x^2+y^2 = k = k * 1
=> x^2 + y^2 = k(x^2 + 2xy - y^2)/2
Divide throughout by xy
=> 2 (x/y) + 2 (y/x) = k (x/y) + 2k - k (y/x)
Let x/y = t
=> (2-k)t^2 + -2kt +(2+k)=0
since x/y is real, so D ≥ 0
=> 4k^2 - 4 (2-k)(2+k) ≥ 0
4k^2 - 4(4-k^2) ≥ 0
8k^2 -16 ≥ 0
k^2 ≥ 2 and k should be +ve only
so k ≥ root2
so min value= sqrt (2)
[Credits : Bruce Wayne]

Method 2:
x^2 + 2xy - y^2 = 2
x = asinQ
y = acosQ
so x^2 + y^2 = a^2
a^2sin^Q + 2a^2sinQ * cosQ - a^2cos^2Q = 2
a^2((sin^2Q - cos^2Q + 2sinQ * coSQ)=2
a^2((sin2Q - cos2Q) = 2
a^2 = 2/(sin2Q-cos2Q)
now max value of sin2Q - cos2Q=root2
so a^2 = 2/root2
so a^2 = root2
so min value will be root2
[Credits : @hemant_malhotra ]

• 2^(1/(x^2 - x + 1)) will be maximum when x^2 - x + 1 is minimum.
Differentiate and equate to 0 => 2x - 1 = 0
x = 1/2
when x = 1/2, x^2 - x + 1 = 1/4 - 1/2 + 1 = 3/4
maximum value is 2^(1/(3/4)) = 2^(4/3)

71

102

61

153

42

127

68