CAT Question Bank  Functions


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.359

@rowdyrathore 704 ?.......................

1+2+4+7+11+16........................and so on till 30th term

f(1)=f(3) = f(5) = and so on
so f(511) =3
@SujanChhetri

@RowdyRathore F(x) = 3X  1.

@RowdyRathore 2009(5!) + 11.

@RowdyRathore It has to be 36 only, since f(1) = 1 and f(1/2) = 8, and there is no possibility of F(1/3) being negative.

F(x) = x^4360x^2+400
F(x) = (x^2+20)^2  400x^2
F(x) = (x^220x+20)(x^2+20x+20) = Prime Number
Since the value of second factor is always positive and greater than 1 therefore, 1st factor has
to be equals to 1.
x^220x+20 = 1
x^220x+19= 0
On solving,
x = 1, 19.
Putting back the values in the original equation we get f(x) = 41 and f(x) = 761.So, the sum will be 41+761 = 802

@RowdyRathore Equation is x^212x+35, and a+b+c = 112+35 = 24