CAT Question Bank  Functions

Number of Questions  30
Topic  Functions
Answer key available?  No
Source  Curated Content

Q1) f(x) is a polynomial of degree six, in which the coefficient of x^6 is 1. If f(0) = 1, f(1) = 4, f(2) = 9, f(3) = 16, f(4) = 25 and f(5) = 36, find the value of f(6).

Q2) A function f(x) is defined for all real values of x as 2f(x) + f(1 – x) = x^2. What is the value of f(5)?
(a) 10
(b) 17
(c) 34/3
(d) Cannot be determined

Q3) If F(x) = x^4  360x^2 + 400 (for any integral value of x) and if F(x) is a prime number, then what is the sum of all possible values of F(x)?

Q4) Evaluate f(x) if f(2x + 1) = 6x + 2

Q5) The graph of the function f(x) = a(x + 1)^3 passes through the point (1, 4). What is f(3)?

Q6) f(x)f(y) = f(x+y)
If f(1) = 0.3333333...
Find the value of f(1) + f(3) + f(5) + … up to infinity

Q7) If f(x) = 2x^2 + 6x  1 and g(x) = x + 5 then the value of f(g(f(g(6))) is

Q8) If f(x) = log((1+x)/(1x)), then f(x) + f(y) ?
a) f(x + y)
b) f(1 + xy)
c) (x + y) f(1 + xy)
d) f ((x +y) / (1+xy))

Q9) A function f(x) defined for all real values of x as 2f(x) + f(1x) = x^2. Find f(5)?

Q10) Let f(x) be a function with the two properties:
a) for any two real numbers x and y, f(x + y) = x + f(y)
b) f(0) = 2
What is the value of f(98) ?

Q11) F(x) is a Polynomial of degree 5 & leading coefficient is 2009.
F(1) = 1
F(2) = 3
F(3) = 5
F(4) = 7
F(5) = 9
Find F(6)

Q12) A function f(x) is said to be strictly increasing if f (x1) > f (x2) for x1 > x2. The number of strictly increasing functions that can be defined from set A with 4 positive integers to set B with 6 positive integers is?

Q13) f(x) be a function for every real x, f(x+1)  f(x) = f(x2)  f(x1) and f(3) = 3 then find f(511) ?

Q14) A polynomial f(x) with positive integer coefficients satisfies f(1) = 12 and f(12) = 2080. Find the last three digits of f(10).

Q15) If we define a function f(x) on natural numbers as f(x + 1) = f(x) + x and f(1) = 1, what is the sum f(1) + f(2) + f(3) + ... + f(30)?

Q16) f(x) = ax^2 + bx + c where a is not equal to 0.
f(7) = 2f(5) and 5 is one of the root of f(x) = 0.
Find a + b + c

Q17) Function f(x) is defined for all positive integers that satisfy the condition:
f(1) + f(2) + f(3) + ... + f(p) = p^2 × f(p)
If f(1) = 2009, then what is the value of f(2008)?

Q18) f(x) + f (1/x) = f(x) f(1/x)
f(4) = 6
Find f(6).

Q19) Function f(x) is a continuous function defined for all real values of x, such that f(x) = 0 only for two distinct real values of x. It is also known that
f(6) + f(8) = 0
f(7).f(9) > 0
f(6).f(10) < 0
f(0) > 0 and f(1) < 0
How many of the following statements must be true?
I. f(1).f(2).f(3) < 0
II. f(3).f(5).f(7).f(9) > 0
III. f(7).f(8) < 0
IV. f(0) + f(1) + f(9) + f(10) > 0(a) 1
(b) 2
(c) 3
(d) 4

f(6) + f(8) = 0
indicates a root lies between 6 and 8
f(7).f(9) > 0
indicates f7 and f9 lie on the same side of the X axis
So, we can say
(a) root lies bw 6 and 7, and both 7 and 9 are either +ve or negative
f(6)f(10) 0 and f(1) < 0
indicates a root lies between 0 and 1
f(x) = 0 only for two distinct real values of x << Only two distinct roots. Both have been discovered.
f(0) > 0
hence it begins as a curve above the X axis, somewhere between (0,1) has a root, then becomes ve. The second root arrives between (6,7) and beyond this curve again becomes +veSo
I. f(1).f(2).f(3) < 0 << All three values are negative. Hence, true
II. f(3).f(5).f(7).f(9) > 0 << f3,f5 are ve whereas f7,f9 are +ve Hence true
III. f(7).f(8) < 0 << Both are +ve hence false
IV. f(0) + f(1) + f(9) + f(10) > 0 << f0,f9,f10 are +ve while f1 is ve
However it being a continuous curve with two roots, it cannot be predicted what will be the negative value. so not a "must be true" statement.So ans 2
[Credits : @hemant_malhotra]