Question Bank  Algebra  Shashank Prabhu, CAT 100 Percentiler

@shashank_prabhu yes option b

@shashank_prabhu (3^14+3^12)(3^11+3^13)
2103^11
hence b

@shashank_prabhu g(21)=g(19)=7

@shashank_prabhu x= 3 to 7

@shashank_prabhu (1+1/21/101)= 301/202 = 1.48

@shashank_prabhu none of these

@shashank_prabhu 6a+90d=372
a+15d=62

a7 = a1 + 6d
a13 = a1 + 12d and so on.
We need a1 + 15d

@shashank_prabhu Can you please provide a solution for this? I got 12 values. All the Prime numbers including 2. The other values were 9 and 25. What is the appropriate method to do this?

@shreyasnegi13
There are 10 primes in the given range.
4 also satisfies
9 and 25 won't work because we would already have two 3s and 5s respectively in the numerator
So 10 + 1 = 11 values.