Question Bank - 100 CAT level questions on Time, Speed and Distance topic
No of steps S= 30x+26 =18x+34 (where x=speed of escalator in steps/sec)
solving above eqn we get x=2/3 step/sec
hence number of steps = 20*2/3+26 =46
so ans is B
X= distance from Baghbazar Ghat to Ahiritola Ghat
S is swimmer speed and R is river speed
20/(S-R)=3*20/(S+R) solving this we get S=2R
Now time taken by log to travel distance BA is equal to time taken by swimmer to travel from ahirtola to Howrah and back to Bagh bazar. So,
X/R=20/R+(20+X)/3R (equate S=2R)
3X= 80+X (multiply by 3R)
so X=40 is the answer
i.e Option d
A(Arpit Speed)=2.5P (prakash speed)
d= distance from P to point of return
2 +5(d-10)/A =10/P (time taken by prakash and Arpit are same)
i.e ans is a
x = distance neha walk at g speed to pickup point
y= distance nitin drives at b speed to pickup point
x/g = y/b =30/2 =15
so ratio is 1:3
hence C is ans
E= Escalator speed
B= speed of B
so speed of A=2B
time taken by A = 60Steps/2B = (T-60)/E
time taken by B = 40Steps/B =(T-40)/E
Solving above you get T=120
a= speed of train starting from P
b= speed of train starting from Q
Similarly PR.b/((a+b).a)=25 ....(2)
dividing 1 by 2
so ans is b
Kat Gupta last edited by aneeeshp
Total 40 min adding 5 min lead
@mbatious relative speed = 40+60=100
0.2/100*10 = 0.02 or 20mtrs
Fastest one = D+D-0.2 total distance
Slower one = 0.2 total distance
Time is same so
D=1/4 or 250 mtr
Shikha .........48min drive......rohan...................concert
meet somewhere in between and saves 8 min drive either side
so rohan covers distance worth 40min drive in the same time shikha covers distance worth 8min drive
therefore ratio of speed = 5:1 ( rohan:shikha)
hence auto rikshaw speed = 60/5 = 12kmph
Baibhav Raj last edited by
Anurag MN last edited by aneeeshp
A faulty clock gains 10 minutes every hour. If the time is set correctly at 12 Noon on 1st Jan 2010, then how many times will its minute-hand and hour-hand meet in the next 24 hours
24:28 is the ratio of correct:faulty clock
The new speed of minute hand will be 70 div/60 min.
The new speed of hour hand will be 5.8333 div/60 min.
so there are 28 * 60 divisions.
And the relative speed is 64.167.
28 * 60/64.167=26.18 ==> 26 meetings.
@mbatious 1296 km . . .
@mbatious 17.5 km .
@mbatious 4.28 km/hr
@mbatious 8.333 pm
The answer is 15, not 56.
When running in the same direction : If the ratio of speeds of two athletes (in the most reducible form) is a : b, the number of distinct meeting points on the track would be would be |a – b|
A and B will meet at |1 - 2| = 1 point.
A and C will meet at |1 - 3| = 2 points
A and D will meet at |1 - 4| = 3 points
A and E will meet at |1 - 5| = 4 points
A and F will meet at |1 - 6| = 5 points
A and G will meet at |1 - 7| = 6 points
So the distinct points are only 4+5+6=15.
Because 1,2,3 points coincide with 6 distinct points.
still not convinced?
draw a circle of 420 m and try plotting distinct points.you will 100% understand.