# Question Bank - 100 CAT level questions on Time, Speed and Distance topic

• @mbatious
Shikha .........48min drive......rohan...................concert
...........shikha/rohan..........................................concert

meet somewhere in between and saves 8 min drive either side
so rohan covers distance worth 40min drive in the same time shikha covers distance worth 8min drive
therefore ratio of speed = 5:1 ( rohan:shikha)
hence auto rikshaw speed = 60/5 = 12kmph

• Where will i find the answers?
Please tell @mbatious @arvindkjha @Aparajita @Prem-Mora

• A faulty clock gains 10 minutes every hour. If the time is set correctly at 12 Noon on 1st Jan 2010, then how many times will its minute-hand and hour-hand meet in the next 24 hours

24:28 is the ratio of correct:faulty clock

The new speed of minute hand will be 70 div/60 min.
The new speed of hour hand will be 5.8333 div/60 min.

so there are 28 * 60 divisions.
And the relative speed is 64.167.
so,
28 * 60/64.167=26.18 ==> 26 meetings.

• @mbatious 1296 km . . .

• @mbatious 17.5 km .

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• @mbatious 4.28 km/hr

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• @mbatious 8.333 pm

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• The answer is 15, not 56.

When running in the same direction : If the ratio of speeds of two athletes (in the most reducible form) is a : b, the number of distinct meeting points on the track would be would be |a – b|

A and B will meet at |1 - 2| = 1 point.
A and C will meet at |1 - 3| = 2 points
A and D will meet at |1 - 4| = 3 points
A and E will meet at |1 - 5| = 4 points
A and F will meet at |1 - 6| = 5 points
A and G will meet at |1 - 7| = 6 points

So the distinct points are only 4+5+6=15.
Because 1,2,3 points coincide with 6 distinct points.

still not convinced?
draw a circle of 420 m and try plotting distinct points.you will 100% understand.

• @mbatious 200

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• @mbatious what the a swer

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