Solved ? -

Topic - Quant Mixed Bag

Source - Elite's Grid CAT Preparation Forum ]]>

Solved ? -

Topic - Quant Mixed Bag

Source - Elite's Grid CAT Preparation Forum ]]>

[OA : 931]

]]>[OA : 240]

]]>[OA : 0]

]]>[OA : 5796]

]]>a) If the king had 6 sons what is the minimum number of gold coins that king could have given his sons?

b) If the king gave less than 100 coins on the whole to his sons, what is the maximum number of sons he could have had? ]]>

b) 1 + 2 + 3 + 5 + 8 + 13 + 21 + 34 so 8 sons ]]>

[OA : 125]

]]>[OA : 16]

]]>[OA : 504]

]]>[OA : 444]

]]>[OA : 150]

]]>[OA : 19/35]

]]>[OA : 240]

]]>[OA : 13]

]]>The maximum distance is 5+5+5+5+5+5 = 30.

and 1,3,5 odd so sum of odd+odd+odd+odd+odd+odd=even so sum will alwys be even

so 6,8,10,12.......30 possible

so 30 = 6 + (n - 1) * 2

so n=13 different possible ]]>

[OA : 29C9]

]]>Q1) What is the minimum possible number of red covered diaries?

a) 15

b) 17

c) 18

d) 19

Q2) If the total number of diaries is 52, find the minimum number of pink covered diaries that would be required?

a) 14

b) 15

c) 16

d) 19

She has to make sure that Sana gets at least 3 and at most 6 chocolates. In how many ways can this be done? ]]>

a + b + c + d + e = 15

where 3 < = a < = 6

so (3 + a') + b + c + d + e = 15 where a' < = 3

so a' + b + c + d + e = 12

so (12 + 5 - 1)C(5 - 1) = 16c4

now this will include case where a1' > 3

so put a' = 4 + a''

4 + a'' + b + c + d + e = 12

a'' + b + c + d + e = 8

so (8 + 5 - 1)C(5 - 1) = 12C4

so 16C4 - 12C4 = 1325

Method 2 :

3 + a + b + c + d = 15

so a + b + c + d = 12

so (12 + 4 - 1)C(4 - 1) = 15C3

4 + a + b + c + d = 15

so a + b + c + d = 11

so 14c3

15c3 + 14c3 + 13c3 + 12c3 = 1325

[OA : 30]

]]>OA : 19C3 - 4(9C3)

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