Discussion Room : Quant

If 76/(4+√7+√11)=p+q√7+r√11+s√77 then p+q+r+s=?

@rohitchopra01 said in Discussion Room : Quant:
If 76/(4+√7+√11)=p+q√7+r√11+s√77 then p+q+r+s=?
Multiply both sides by (4 + 71/2 + 111/2)
76 = (4 + 71/2 + 111/2)p + 71/2(4 + 71/2 + 111/2)q + 111/2(4 + 71/2 + 111/2)r + 771/2(4 + 71/2 + 111/2)s
Expand out:
76 = 4p + 71/2p + 111/2p + 71/24q + 7q + 771/2q + 111/24r + 771/2r + 11r + 771/24s + 111/27s + 71/211sNow get everything together:
76 = (4p+7q+11r) + 71/2(p+4q+11s) + 111/2(p+4r+7s) + 771/2(q+r+4s)Rewrite the LHS:
76 + 0 * 71/2 + 0 * 111/2 + 0 * 771/2 = (4p+7q+11r) + 71/2(p+4q+11s) + 111/2(p+4r+7s) + 771/2(q+r+4s)So we have the following system of equations:
4p + 7q + 11r = 76
p + 4q + 11s = 0
p + 4r + 7s = 0
q + r + 4s = 04 equations in 4 unknowns. Solve.

Find sum of
√{5+√[11+√【19+√(29..........To infinity

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A and B are three digit numbers such that three times their product is equal to six digit number AB. Find the sum of digits of six digit number AB?

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Gordon, an inhabitant of Nibiru, evaluated an expression and arrived at a twodigit answer ‘ 8β’.
Which of the following could be the expression evaluated by Gordon?
a) 2β ^2 – 5β + 3
b) 2β ^2 + 5β + 3
c) 2β ^2 + 6β – 1
d) 2β ^2 + 4β – 2
Help me!!!

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@zabeer A function F(n) is defined as F(n1)=1/(2F(n)) for all natural numbers 'n'. If F(1)= 3,then what is the value of (F(n))+(F(2))+.....+(F(1000))? ( Here (x) is equal to the greatest integer less than or equal yo 'x')
Options:1. 1001,
2. 1002
3. 3003
4. None of these
Can anyone please help?

The units digit of each of two natural numbers, X and Y, when expressed in the number system to the base n is a. If the units digit of (x+y)/2 when expressed to the base n is either 2 or 5, find n.
#QA
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