# Discussion Room : Quant

• If 76/(4+√7+√11)=p+q√7+r√11+s√77 then p+q+r+s=?

• If 76/(4+√7+√11)=p+q√7+r√11+s√77 then p+q+r+s=?

Multiply both sides by (4 + 71/2 + 111/2)

76 = (4 + 71/2 + 111/2)p + 71/2(4 + 71/2 + 111/2)q + 111/2(4 + 71/2 + 111/2)r + 771/2(4 + 71/2 + 111/2)s

Expand out:
76 = 4p + 71/2p + 111/2p + 71/24q + 7q + 771/2q + 111/24r + 771/2r + 11r + 771/24s + 111/27s + 71/211s

Now get everything together:
76 = (4p+7q+11r) + 71/2(p+4q+11s) + 111/2(p+4r+7s) + 771/2(q+r+4s)

Rewrite the LHS:
76 + 0 * 71/2 + 0 * 111/2 + 0 * 771/2 = (4p+7q+11r) + 71/2(p+4q+11s) + 111/2(p+4r+7s) + 771/2(q+r+4s)

So we have the following system of equations:
4p + 7q + 11r = 76
p + 4q + 11s = 0
p + 4r + 7s = 0
q + r + 4s = 0

4 equations in 4 unknowns. Solve.

• Find sum of
√{5+√[11+√【19+√(29..........To infinity

• @zabeer x=8 the value turns out to be 108 u should always look for a no which can create max difference between the give nos like (8 and 6) and (11 and 8)

• A and B are three digit numbers such that three times their product is equal to six digit number AB. Find the sum of digits of six digit number AB?

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• Gordon, an inhabitant of Nibiru, evaluated an expression and arrived at a two-digit answer ‘ 8β’.
Which of the following could be the expression evaluated by Gordon?
a) 2β ^2 – 5β + 3
b) 2β ^2 + 5β + 3
c) 2β ^2 + 6β – 1
d) 2β ^2 + 4β – 2
Help me!!!

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• @zabeer A function F(n) is defined as F(n-1)=1/(2-F(n)) for all natural numbers 'n'. If F(1)= 3,then what is the value of (F(n))+(F(2))+.....+(F(1000))? ( Here (x) is equal to the greatest integer less than or equal yo 'x')
Options:1. 1001,
2. 1002
3. 3003
4. None of these

• The units digit of each of two natural numbers, X and Y, when expressed in the number system to the base n is a. If the units digit of (x+y)/2 when expressed to the base n is either 2 or 5, find n.
#QA
#SolutionPlz

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