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Discussion Room : Quant
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Find sum of √{5+√[11+√【19+√(29..........To infinity
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Response - @vikas_saini Elitmus exam is basically divided into three section. Verbal Ability (20 questions)Problem Solving (20 questions)Quantitative Ability (20 questions)Verbal Ability : In this section, you will find questions of Reading comprehension (RC)and Fill in the blanks and Paragraph jumbles(PJ). RC consists 12 questions, 3 RC sets and per set 4 questions. Fill in the blanks section tests your grammar (6 questions) and PJ consists 4-5 jumbled sentences (2 questions) which you have to rearrange. Strategy :- This is the easiest section of Elitmus. One should pick easy questions from RCs and try to more focus on grammar and PJs. 10 net correct (100 marks) will fetch you 90+ %ile and 12 net correct (120 marks) will fetch you 95+ %ile. Problem Solving :-In this section, you will find questions of data sufficiency, Data interpretation, Logical Reasoning and Crypt arithmetic. Data sufficiency consists 4 questions, crypt arithmetic consists 4 questions and rest 12 questions could come in Data interpretation and Logical reasoning sets. Strategy :- This is the trickiest section of Elitmus. "Accuracy is more important than attempts" here. Crypt arithmetic verbal arithmetic is time consuming set, it takes your 15-20 odd minutes,it requires lot of practice. If you're good at it then you should go for it else leave it. Data sufficiency are bit tricky but one can solve it with accuracy. One must try to pick easy questions from DI or LR portion.4 net correct (40 marks) will fetch 85+ %ile and 6 net correct will fetch 95+ %ile for sure.(adsbygoogle = window.adsbygoogle || []).push({}); Quantitative Ability : In this section you will find questions related to Geometry, Number system, Algebra, Permutation and Combination, Probability. This section is also bit tricky section. Strategy :- Key point of this section is also Accuracy. only 6 net correct (60 marks) can fetch 90+ %ile easily. Material : For Quantitative Aptitude this MBAtious site is more than enough. For Problem Solving, Data Sufficiency and pretty good LR and DI sets are also available here. Do google for Crypt Arithmetic practice sets. For Reading Comprehension and para jumble solve CAT question paper from year 2003-2008. In grammar they ask easy questions just work on your basics. To practice mocks let me give you a link. https://testpot.com/
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@vinaycat2017 nor live in any other Asian country.
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Q6) Six-friends - Rishi, Rajesh, Ramesh, Rakesh, Rupesh and Rishikesh - are of different heights and different weights. A person's weight (in KG) divided by his square of height (in metres) is called his Body Mass Index(BMI). The weights of the friends are 58kg, 60kg, 65kg, 70kg, 76kg and 85kg in no particular order. The heights of the friends are 150cm, 155cm, 160cm, 165cm, 170cm and 180cm in no particular order. Further, it is known that: Rajesh is taller than Ramesh.Rajesh is neither the tallest nor the heaviest.Rakesh is the second lightest person among the six friends.Ramesh is neither the shortest nor the lightest and occupies the even number place in height when arranged in descending order.One of the friends is the tallest as well as the third lightest.Ramesh is heavier than Rakesh.In one of the height and weight parameters, Rishi was second highest followed by Rupesh. One of the friends occupy the same place in the list of height and weight when arranged in descending orders.Over time, the heights and weights of each of the friends changed but the positions of the friends with respect to height and weight remained the same. Which of the following is definitely true?a) The BMI of Rupesh is greater than that of Rajeshb) The BMI of Rishikesh is less than that of Rakeshc) The BMI of Rupesh is greater than that of Rishikeshd) The BMI of Ramesh is greater than that of Rakesh Which of the following is the correct order of BMI?a) Rakesh > Rupesh > Rajesh > Rishikeshb) Rupesh > Rakesh > Rajesh > Rishikeshc) Rakesh > Rupesh > Rishikesh > Rajeshd) Rupesh > Rakesh > Rishikesh > Rajesh(adsbygoogle = window.adsbygoogle || []).push({}); [Answer : Option C, Option A] complete solution kindly

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