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General Queries

mbatious Global Moderator last edited by aneeeshp

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Discussion Room : VARC
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Effective strategies are very important for writing Hong Kong Phone Number List to your opt in email list, as your goal is to achieve profitable results with each email. In other words determine long and short-term goal to achieve from these emails that you will be writing to your opt in email list. Hong Kong Phone Number List Here long-term goal is to make your opt in email list feel that you are the best business or person to buy from and your products Hong Kong Phone Number List solves their problem completely. Short terms goals are determined Hong Kong Phone Number List according to the product you are promoting, but the basic concept is to conditioned the mind of your opt in email list to accept you and your business credible to buy from. At the same time keep in mind Hong Kong Phone Number List your personal goal is to get profitable business results. Keeping this in mind most important part that needs attention is the email subject lines, Hong Kong Phone Number List that you write for your email opt in list. You have to write the subject line that makes them open the Hong Kong Phone Number List and read it. Knowing what motivates your customer is the key to writing emails that they will open and act upon. Here are the following main reasons Hong Kong Phone Number List you have to keep in mind: 1. Established relationship with the opt in email recipients: The 2006 research from "Double Click" says that if email recipients know who their emails are from then 65% of them will open the email for sure. 75% of the recipients will open the Hong Kong Phone Number List if it is from a reputable brand business.(adsbygoogle = window.adsbygoogle || []).push({});
Discussion Room : Quant
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@zabeer A function F(n) is defined as F(n-1)=1/(2-F(n)) for all natural numbers 'n'. If F(1)= 3,then what is the value of (F(n))+(F(2))+.....+(F(1000))? ( Here (x) is equal to the greatest integer less than or equal yo 'x') Options:1. 1001, 2. 1002 3. 3003 4. None of these Can anyone please help?
Discussion Room : Preparation Strategies / Admission
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Response - @vikas_saini Elitmus exam is basically divided into three section. Verbal Ability (20 questions)Problem Solving (20 questions)Quantitative Ability (20 questions)Verbal Ability : In this section, you will find questions of Reading comprehension (RC)and Fill in the blanks and Paragraph jumbles(PJ). RC consists 12 questions, 3 RC sets and per set 4 questions. Fill in the blanks section tests your grammar (6 questions) and PJ consists 4-5 jumbled sentences (2 questions) which you have to rearrange. Strategy :- This is the easiest section of Elitmus. One should pick easy questions from RCs and try to more focus on grammar and PJs. 10 net correct (100 marks) will fetch you 90+ %ile and 12 net correct (120 marks) will fetch you 95+ %ile. Problem Solving :-In this section, you will find questions of data sufficiency, Data interpretation, Logical Reasoning and Crypt arithmetic. Data sufficiency consists 4 questions, crypt arithmetic consists 4 questions and rest 12 questions could come in Data interpretation and Logical reasoning sets. Strategy :- This is the trickiest section of Elitmus. "Accuracy is more important than attempts" here. Crypt arithmetic verbal arithmetic is time consuming set, it takes your 15-20 odd minutes,it requires lot of practice. If you're good at it then you should go for it else leave it. Data sufficiency are bit tricky but one can solve it with accuracy. One must try to pick easy questions from DI or LR portion.4 net correct (40 marks) will fetch 85+ %ile and 6 net correct will fetch 95+ %ile for sure.(adsbygoogle = window.adsbygoogle || []).push({}); Quantitative Ability : In this section you will find questions related to Geometry, Number system, Algebra, Permutation and Combination, Probability. This section is also bit tricky section. Strategy :- Key point of this section is also Accuracy. only 6 net correct (60 marks) can fetch 90+ %ile easily. Material : For Quantitative Aptitude this MBAtious site is more than enough. For Problem Solving, Data Sufficiency and pretty good LR and DI sets are also available here. Do google for Crypt Arithmetic practice sets. For Reading Comprehension and para jumble solve CAT question paper from year 2003-2008. In grammar they ask easy questions just work on your basics. To practice mocks let me give you a link. https://testpot.com/
Discussion Room : DILR
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Q6) Six-friends - Rishi, Rajesh, Ramesh, Rakesh, Rupesh and Rishikesh - are of different heights and different weights. A person's weight (in KG) divided by his square of height (in metres) is called his Body Mass Index(BMI). The weights of the friends are 58kg, 60kg, 65kg, 70kg, 76kg and 85kg in no particular order. The heights of the friends are 150cm, 155cm, 160cm, 165cm, 170cm and 180cm in no particular order. Further, it is known that: Rajesh is taller than Ramesh.Rajesh is neither the tallest nor the heaviest.Rakesh is the second lightest person among the six friends.Ramesh is neither the shortest nor the lightest and occupies the even number place in height when arranged in descending order.One of the friends is the tallest as well as the third lightest.Ramesh is heavier than Rakesh.In one of the height and weight parameters, Rishi was second highest followed by Rupesh. One of the friends occupy the same place in the list of height and weight when arranged in descending orders.Over time, the heights and weights of each of the friends changed but the positions of the friends with respect to height and weight remained the same. Which of the following is definitely true?a) The BMI of Rupesh is greater than that of Rajeshb) The BMI of Rishikesh is less than that of Rakeshc) The BMI of Rupesh is greater than that of Rishikeshd) The BMI of Ramesh is greater than that of Rakesh Which of the following is the correct order of BMI?a) Rakesh > Rupesh > Rajesh > Rishikeshb) Rupesh > Rakesh > Rajesh > Rishikeshc) Rakesh > Rupesh > Rishikesh > Rajeshd) Rupesh > Rakesh > Rishikesh > Rajesh(adsbygoogle = window.adsbygoogle || []).push({}); [Answer : Option C, Option A] complete solution kindly

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General Queries

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