Quant Boosters  Geometry  Raman Sharma  Set 2

Q25) In an isosceles right angled triangle abc . Angle b is right angle . Angle bisector of anglebac is an cut at m to the median bo. Point o lies on hypotenus .om is 20 cm then the value of ab is?


Q26) Two sides of triangle are 10cm and 5cm in length and the length of the median to the third side is 13/2 cm.The area of the triangle is 6√x cm. Then find the value of x.
[OA: 14 cm]

Q27) A triangle has sides of length √13, √17, and 2√5. Compute the area of the triangle

(Credits : Shubham Sharma)

Q28) ABC is an equilateral triangle with side length 7. BP = 3 , CP = 5 . What is the length AP ?
[OA: 8]

AC * BP + AB * CP = AP * BC
7 * 3 + 7 * 5 = 7 * AP
AP = 8
(ptlomy's theorem)
(credits : Varun Kumar Mandal)

Q26) In a ∆ PQR, PQ=QR , angle PQR = 90° and S and T are points on PR such that PS^2 + TR^2 = ST^2 then angle SQT = ?
a. 30
b. 45
c. 60
d. 75[OA : 45]


Q27) In a ∆ABC, ∆ = 6 , abc = 60, r = 1, then 1/a + 1/b + 1/c = ?
[OA: 47/60]

Q28) There is a square ABCD. There is a point P inside this square such that PA = 4, PB = 1, PD = 5. Find area of the square.
[OA : 17]

(credits : Anil Sharma)

Q29) In a ∆ABC , if tanA and tanB are the roots of the of pq(x²+1) = r²x. Then ∆ABC is
a. Right angled
b. Obtuse angled
c. Equilateral
d. Acute angled

pqx^2  r^2x + pq = 0
tanA + tanB = r^2/pq
tanA * tanB = 1
tan(A + B) = tan 90
so A + B = 90, so C = 90
So right angle

Q30) Given AB = AC. Find the measure of angle BAD



r= delta/s s=6 => a+b+c =12 , abc=60
a=3, b=4,c=5
1/a+1/b+1/c=47/60

@raman_sharma How the the length of side BE was computated?

@raman_sharma What is 'y' in your calculation of areas of the triangle? What formula have you used for calculating the area?