Quant Boosters - Kamal Lohia - Set 6
Q20) Visitors to a show were charged Rs. 15.00 each on the first day, Rs. 7.50 on the second day, Rs. 2.50 on the third day and total attendance on the three days were in the ratio 2:5:13 respectively. The average charge per person for the whole show is
a. Rs 3.00
b. Rs 4.50
c. Rs 5.00
d. Rs 7.50
e. Rs 8.00
OA : c (Rs 5.00)
Q21) In a class there are three divisions. The number of students and the average marks in mathematics in the three divisions are 30, 40, 30 and 40%, 30% and 50% respectively. What are the average marks in mathematics of the class?
OA : a (39%)
Q22) Five years ago average age of P and Q was 15 years. Average age of P, Q and R today is 21 years. How old R will be after 10 years.
OA : c (33)
Q23) Shweta took a loan of Rs.24000 for purchasing a TV. After two years, she paid it off by Rs.27840. Find the rate of simple interest.
OA : b (8%)
Q24) There are two equal capacity vessels full of milk solution with milk and water in the ratio 1:3 and 3:5 respectively. If both are mixed in the ratio 3:2, what would be the ratio of milk and water in the new mixture?
a. 3 : 10
b. 4 : 7
c. 3 : 7
d. 9 : 19
e. None of these
OA : c (3 : 7)
Q25) Ram prepares solutions of alcohol in water according to customers' needs. This morning Ram has prepared 27 liters of a 12% alcohol solution and kept it ready in a 27 liter delivery container to be shipped to the customer. Just before delivery, he finds that the customer had asked for 27 liters of 21% alcohol solution. To prepare what the customer wants, Ram replaces a portion of 12% solution by 39% solution. How many liters of 12% solution is replaced? [XAT2012]
OA : b (9)
Q26) A man borrows Rs.6000 at 5% interest, on reducing balance, at the start of the year. If he repays Rs.1200 at the end of each year, find the amount of loan outstanding at the beginning of third year. [XAT2012]
OA : c (4155)
Q27) After allowing a discount of 11.11%, a trader still makes a gain of 14.28%. At how many percent above the cost price does he mark his goods? [CAT1997]
d. None of these
OA : a (28.56%)
Q28) A man invests Rs 3000 at a rate of 5% per annum. How much more should he invest at a rate of 8% per annum, so that he can earn a total of 6% per annum? [CAT1995]
OA : c (1500)
Q29) Last year Mr. Basu bought two scooters. This year he sold both of them for Rs.30,000 each. On one, he earned 20% profit, and on other he made a loss of 20%. What was his net profit or loss? [XAT2005]
a. He gained less than 2000
b. He gained more than 2000
c. He lost less than 2000
d. He lost more than 2000
OA : d (He lost more than 2000)
Q30) What sum of money lent out at compound interest will amount to Rs.968 in 2 years at 10% p.a. Interest being charged annually.
OA : c (800)
zabeer last edited by
So we write 1, 2, 3, φ, 4, 5..
1 - 10 : +1
11 - 20 : +1
21 - 30 : +1
31 - φ0 : +2 (3φ, φ0)
φ1 - 40 : +10 (φ1, φ2, φ3, φφ, φ4, φ5, φ6, φ7, φ8,φ9)
41 - 50 : +1
51 - 60 : +1
61 - 70 : +1
71 - 80 : +1
81 - 90 : +1
91 - 94 : +1
Total = +21
So Age of alien = 94 + 21 = 115
Here the expression has odd number of factors.
Which means it is a perfect square.
Now if N is even expression is odd(e+e+o =o)
And if n is odd expression is still odd(o+o+o=o)
Thus, the square is of an odd positive number.
Putting expression equal to 11^2 satisfies it
And n comes out to be 9
But ,how to ensure that there is no other solution besides this for higher squares????
SO The sum of digits is 6.
the gcd cant be greater than the difference of the two consecutive terms of the sequence
Equating to 41 gives n =20 , nd the numbers are 410 and 451...whose gcd is 41..
59 on equating doesnt give two numbers which hv gcd as 59
X= 10^20000-2^200/ 10^100+2
Hence highest power is 199
Is my solution right?
Remainder of (P-3)!/p=(p-1)/2
Remainder of (p-4)!×(p-3)/p =(p-1)/2
Rem(p-4)!/p = (1-p)/6
Hence rem( 6*(p-4)!/p)= rem((1-p)/p)= 1
12100 =2^2 ×5^2 ×11^2
Number of factors of 12100 less than 110 =
Numbr of factors of 110 less than 110 =7
Hence total factors of 12100 which are less than 110 but do not divide it are 13-7 =6
What is the logic to be used for tgis prob? Could anyone guide?
It will satisfy for 11th digit x=0,7