Question Bank  100 Arithmetic Questions From Previous CAT Papers (Solved)

First cycle :
P(1  x/100)(1 + x/100) = P  441
so (x^2/100) = 441/P  (1)Second cycle :
(P  441) (1  x^2/100) = 1944.81  (2)From (1) & (2)
(P  441) (1  441/P) = 1944.81
(P  441)(P  441) = 1944.81P
P^2  2826.81P + 194481 = 0
P = 2756.25

@master_shifu ...IS their any other way to solve this question?

Work with ratios
Ratio of speed of N & S = 4 : 1
=> Ratio of time taken by N & S = 1 : 4
Total time taken = 1 hour
Time taken by N to cover the distance AB = 1/5 hour = 12 minutes
Time taken by S to cover the distance AB = 4/5 hour = 48 minutes
When the train was late by 20 minutes, total time available = 40 minutes
N doubled the speed, so time taken to cover distance AB = 12/2 = 6 minutes
So, S should cover the distance in 40  6 = 34 minutes
ratio = 6 : 34 = 1 : 6 (approx)

@master_shifu
Can we not calculate the average speed by adding the total distance, i.e 9000 kms and then adding the total time taken , i.e. 25 hours + 24 hours + 1.55(halt in India) and then dividing those figures. Total distance/total time?

@master_shifu In 19 th question CAT 2002 in arithmetic, the answer comes is 43.5

@master_shifu total time taken would be (5+17.5+20) = 42.5

@swatijha Thanks Swati. Corrected the solution.
Mistake was in distance values and is now clean, hopefully :)
Happy learning!