Each angle is 180(p-2)/p.
180-{360}/{p} = k
So 360/p has to be an integer.
360 = 2^3 * 3^2 * 5^1
So there are 4 * 3 * 2 = 24 possibilities, but we exclude 1 and 2, because p > = 3
So , 24 -2 = 22
Hence, choice (c) is the right answer

|x|+2|y|+|z|=4
for |y|=0, |x|+|z|=4 so 4n=4 * 4=16 cases
for |y|=1, y=+-1 and |x|+|z|=2 so 2 * 4 * 2=16 cases
for |y|=2 y=+-2 |x|+|z|=0 so 2 * 1 = 2 cases
so 16+16+2 = 34 integer solutions.

At 3:30, the hour hand would be exactly between 3 and 4
=> 15 deg from both 3 and 4
At 3:30, the minute hand would be exactly at 6
The gap between the hour hand and the minute hand will be
30 deg (between 5 and 6) + 30 deg (between 4 and 5) + 15 deg (between hour hand and 4) = 75 degrees

@pratik0809 It is asked to create subset so that NO two elements sum to 11. So Null set satisfies right ?
Logic here is, for a usual case (without any conditions), we can have 2^n subsets for a set of n elements. Why ? because each element can either be present or not in the subset. So each element can have two options giving a total of 2^n possibilities.
Here, we have 5 pairs and each pair can contribute in 3 ways - First element selected or Second element selected or None is selected.
So total subsets = 3^5 = 243 ways (which includes null set too)