Quant Boosters - Maneesh - Set 3



  • Let x is total profit.
    Both partners will get 0.3x each.
    Remaining 0.4x will be divided in the ratio of 1250/850 => 25/17
    One will get 0.3x+ (10x/42) and other will get 0.3x+(6,8x/42)
    22.6x/42 – 19.4x/42 = 320
    3.2x = 42 * 320
    X = 4200
    Hence total profit is Rs.4200.



  • Q3) A and B enter in to a partnership. A puts in Rs.2000 but at the end of three months, withdraws Rs.500 and again at the end of 8 months withdraws Rs.300. Out of a total profit of Rs.900 at the end of the year, B’s share was Rs.400. Find B’s capital.



  • A’s profit/B’s profit = 5/4
    A’s capital = 2000*3 + 1500 * 5 +1200 *4 = 6000+7500+4800 = 18300
    A’s capital/ B’s capital = 5/4
    B’s capital for 12 months= 4 * 18300/5 = 4 * 3660 = 14640
    B’s capital for one month = 14640/12 = Rs.1220



  • Q4) A, B and C started a business, two times of A’s capital is equal to 3 times of B’s capital and equal to 5 times of C’s capital. Out of a profit of Rs.1550, A’s share is



  • 2A = 3B = 5C
    A : B = 3:2
    B:C = 5:3
    A:B:C = 15:10:6
    A’s share = 1550 * 15/(15+10+6) = 50 * 15 = Rs.750



  • Q5) Raju, Ravi and Ramu invest Rs.15000, Rs.25000 and Rs.30000 respectively in a business. After one year Raju removed his money but Ravi and Raju continued for one more year. If the net profit after 2 years is Rs.25200, then Raju’s share in the profit is:



  • Raju’s capital = 1 * 15000 = 15000
    Ravi’s capital = 2 * 25000 = 50000
    Ramu’s capital = 2 * 30000 = 60000
    Raju’s share = 25200 * 15000/125000 = 25200 * 3/25 = 1008 * 3 = Rs.3024



  • Q6) Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. Find the sum placed on simple interest.



  • Let Principal is P
    P * 3 * 8/100 = 1/2(4000(110/100)^2-4000)
    6P/25 = 1/2(40 * 121 -4000) = 1/2(4840-4000) = 1/2 (840) = 420
    P = 25 * 420/6 = 25 * 70 = 1750



  • Q7) Find the difference between simple interest and compound on Rs. 1200 for one year at 10% per annum reckoned half-yearly?



  • P = 1200 N = 1 YEAR R= 10%
    SI = 1200 * 1 * 10/100 = 120 RS
    CI = 1200(1+(10/2)/100)^2 – 1200
    = 1200 * 441/400 -1200
    = 1200 * (441/400 – 1)
    = 1200 * 41/400
    = 123 RS
    Difference = 3RS



  • Q8) The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?



  • (15000(1+R/100) ^2-15000) – 15000 * 2 * R/100 = 96
    15000((1+R/100) ^2-1 -2R/100) = 96
    15000(1+2R/100+R^2/10000-1-2R/100) = 96
    15000 * R^2/10000 = 96
    3R^2 = 192
    R^2 = 64
    R = 8%



  • Q9) The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. Find the sum.



  • Let P = 1 Rs
    SI = 1 * 2 * 4/100 = 2/25
    CI = 1 * (104/100)^2 – 1 = 676/625-1 = 51/625
    CI-SI = 51/625 – 2/25
    = 51-50/625 = 1/625
    Hence for 1 Rs sum difference is 1/625 Rs
    So for getting 1 Rs difference Sum will be 625 Rs.



  • Q10) The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. Find the period (in years)



  • Total Amount = 30000+4347 = 34347
    34347 = 30000 * (1+7/100) ^N
    (107/100)^N = 34347/30000 = 11449/10000
    (107/100)^N = 11449/10000
    N = 2 Years



  • Q11) Ram’s speed is with the current is 10 m/s and speed of current is 2 m/s .Then What’s Ram’s speed against current?



  • Let speed of current y = 2 m/s
    Let Ram’s speed in still water is x m/s
    x+2 = 10 m/s
    x = 8 m/s



  • Q12) A boat can travel with a speed of 15 m/s in still water. If the speed of the stream is 5 m/s, find the time taken by the boat to go 100 m downstream?


Log in to reply