Quant Boosters  Maneesh  Set 1

Q5) The HCF of two numbers is 12 and their sum is 288. How many pairs of such numbers are possible?

Let numbers be 12a, 12b
12(a+b) = 288
a+b = 24 and a and b are co prime
Hence(1,23)(5,19)(7,17)(11,13)
Hence 4 pairs available.

Q6) HCF of 2 numbers are 12 and their product is 31104. How many such numbers are possible?

Let numbers are 12a n 12b
144ab = 31104
ab = 216
a and b are coprime
(1,216)(8,2)
Only two pairs possible.

Q7) Find the Highest five digit number that is divisible by each of the numbers 24, 36, 45 and 60?

LCM (24,36,45,60) => 24 = 2^3 * 3
36 = 3^2 * 2^2
45 = 3^2 * 5
60 = 2^2 * 3 * 5
LCM = 2^3 * 3^2 * 5 = 360
So we have to find highest five digit multiple of 360
99999 mod 360 = 279
so answer 99999279 = 99720

Q8) Find the lowest number which gives a remainder of 5 when divided by any of the numbers 6, 7, 8 ?

LCM(6, 7, 8) = 168
number = 168 + 5 = 173

Q9) What is the smallest number which when divided by 9,18 and 24 which leaves a remainder of 5, 14 and 20 respectively

Q10) In a book store “OM INNOVATIVE BOOK STORE“ is flashed using neon lights. The words are individually flashed at intervals of 8/3, 16/3 , 14/3 and 15/2 seconds respectively and each word is put off after a second. The least time after which the full name of the book store can be read for a second?

Q11) A number when divided by 3, 4, 5 and 6 always leave a remainder 2, but leaves no remainder when divided by 7. What is the lowest such number possible?

LCM(3, 4, 5, 6) = 60
Number of the form 60a + 2
60a + 2 = 7b
lowest such number > 182 when a = 3 & b = 26

Q12) For how many pairs (a,b) of natural numbers is the LCM of a and b 2^3 * 5^7 * 11^13?

Let one of the number contains 2^3
Other may contain 2^0,2^1,2^2,2^3 > 4 possibilities
Number of ordered pairs > 2 * 4 – 1 = 7 (since (2^3,2^3) required only once)
Similarly powers of 5 > 2 * 8 – 1 = 15
Powers of 11> 2 * 14 – 1 = 27
Total 7 * 15 * 27 = 2835

Q13) An Egyptian fraction has a numerator equal to 1 and its denominator is a positive integer. What is the maximum number of Egyptian fractions such that their sum is equal to 1 and their denominators are equal to 10 or less?

Possible numbers 1/2 ,1/3,1/4,1/5,1/6,1/7,1/8,1/9
Out of which 1/5, 1/10, 1/7, 1/9 can be eliminated since it wont give sum of 1
Similarly 1/4 and 1/8 can be eliminated.
So remaining 1/2, 1/3 and 1/6 = > 1/2 + 1/3 + 1/6 = 1
So maximum number > 3

Q14) What is the minimum number of square marble tiles required to tile a floor of length 2 meters 56 cm and width 3 m and 36 cm ?

Length = 256 cm
Width = 336 cm
Square side > HCF[256,336] = 16
No of tiles required = 256 * 336/16 * 16 = 336

Q15) Three containers having 9/2, 13/4 and 19/3 litres of three different cold drinks are to be served equally to all guests in a party such that each one gets maximum. How many maximum number of guests could be entertained ?

HCF [9/2 , 13/4 , 19/3] = 1/12
Maximum number of guests = 9/2 * 12 + 13/4 * 12 + 19/3 * 12 = 54 + 39 + 76 = 169