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  • RE: Question Bank - 100 Algebra Questions From Previous CAT Papers (Solved)

    @visheshsahni

    No one is perfect here yaar and if you find a mistake in a solution and know the right answer, least thing to do is to share the solution. That's how a forum (should) function right ? :)
    Corrected the question.

    posted in Quant BBQ - Best of Best Questions
  • RE: Question Bank - 100 CAT level questions on Time, Speed and Distance topic

    t + t/12 = 9 (time taken in the return journey is 1/12th the time taken for the onward journey)
    t = 108/13 = 8.30 hours
    t + t/6 = 9.68 hours?

    posted in Quant BBQ - Best of Best Questions
  • CAT 2018 Syllabus and Study Material

    CAT (Common Admission Test) is an online exam to test a candidate’s Verbal Ability (VA), Reading Comprehension (RC), Logical Reasoning (LR), Quantitative Ability (QA) and Data Interpretation (DI) skills. CAT is conducted by IIM. Students who aim to get admission in IIMs, IITs and IISc should have an excellent CAT score. They select students for their business administration and management programmes based on this score. CAT 2018 registrations started on 8th Aug 2018. The last date for registration is 19th Sept 2018. Correction window opens in the last week of September 2018. The exam will be conducted on the 25th of Nov 2018. Before starting with the preparation for CAT it is essential to understand the paper pattern and syllabus for CAT

    Syllabus for CAT

    Verbal Ability and Comprehension Reading (VARC) Syllabus for CAT 2018:
    The total number of questions asked in this section are 34 out of which 24 are MCQ type and 10 are Non MCQ type.

    Logical Reasoning (LR) syllabus for CAT 2018:
    The total number of questions asked in this section are 16 out of which 12 are MCQ type and 2 are Non MCQ type. Key subtopics to focus are:

    1. Clocks
    2. Binary Logic
    3. Blood Relations
    4. Assumption
    5. Conclusion
    6. Calendars
    7. Seating Arrangement
    8. Logical Sequence
    9. Premise
    10. Linear & Matrix Arrangement

    Data Interpretation (DI) syllabus for CAT 2018:
    The total number of questions asked in this section are 16 out of which 12 are MCQ type and 4 are Non MCQ type. Key subtopics to focus are:

    1. Data Tables
    2. Bar diagrams
    3. Graphs
    4. Data charts
    5. Pie charts
    6. Data analysis

    Quantitative analysis (QA) syllabus for CAT 2018:
    The total number of questions asked in this section are 34 out of which the number of MCQ type are 24-27 and Non-MCQ are 7-10. This is as per the previous 2 years Quant section.

    1. LCM and HCF
    2. Percentages
    3. Profit and Loss
    4. Simple and Compound Interest
    5. Speed, Time and Distance; Time and Work; Averages etc
    6. Ratio and Proportion
    7. Geometry (6-8 questions)
    8. Algebra (5-7 questions)
    9. Venn diagrams; other topic questions (2-3)
    10. Pure Math (1-2 questions)
    11. Complex Numbers
    12. Quadratic Equations;
    13. Linear Equations
    14. Binomial Theorem
    15. Progressions; Logarithm
    16. Inequalities
    17. Surds and Indices
    18. Probability Functions
    19. Permutation and Combination
    20. Mixtures and Alligations
    21. Set Theory
    22. Trigonometry
    23. Coordinate Geometry

    There are many learning Apps like BYJU’S which help you with CAT preparation with required study materials and practice tests like CAT mock test.

    For more updates on CAT 2018, students can visit the official website of BYJU’S which is India’s largest education company and largest k-12 learning App in India. Students are also suggested to subscribe to our YouTube channel.

    posted in Test Preparation Strategy
  • RE: Question Bank - Algebra - Shashank Prabhu, CAT 100 Percentiler

    @shreyasnegi13
    There are 10 primes in the given range.
    4 also satisfies
    9 and 25 won't work because we would already have two 3s and 5s respectively in the numerator
    So 10 + 1 = 11 values.

    posted in Quant BBQ - Best of Best Questions
  • RE: Discussion Room : DILR

    @laavanya-ramaul

    120 = I + II + III (Where I - number of students who attended exactly one interview, II - exactly two interviews and III - exactly three interviews)
    I > II > III
    III is at-least 1

    a) maximum number of students who attended exactly 3 companies.
    We have to minimize I and II.
    Let say x people attended all three. and let x + 1 attended exactly two companies and x + 2 attended exactly one company.
    So 3x + 3 = 120
    x = 39

    posted in Discussion Room
  • RE: Discussion Room : Quant

    @vinaycat2017

    120 rupees is the original price
    25 rupees down payment means 95 rupees is what we are "Borrowing" from the shop.
    Amount paid in instalments = 25 * 4 = 100
    So 100 - 95 = 5 is the interest
    Now this interest gained (Rs 5) is through the interest gained in the available amount month by month.
    5 = 95R/(12 * 100) + 70R/(12 * 100) + 45R/(12 * 100) + 20R/(12 * 100)
    5 = 230R/(12 * 100)
    R = 6000/230 = 26.09%

    posted in Discussion Room
  • RE: CAT Question Bank - Time & Work

    @Ishita 120 is correct. Can you share your detailed approach so that others will benefit :)

    posted in Quant - Boosters
  • RE: CAT Question Bank - Time & Work

    @Ishita 22.5 is the right answer.

    A does 3x and B does x amount of work in a given amount of time.
    as work is inversely proportional to the time taken, A takes t days and B takes 3t days to complete a given amount of work.
    we know 3t - t = 60 days
    t = 30 days
    So A takes 30 days and B takes 30 + 60 = 90 days

    Together, 1/30 + 1/90 = 4/90 of work will be completed and it will take 90/4 = 22.5 days to finish the work together.

    posted in Quant - Boosters
  • RE: Gyan Room : Arithmetic - Concepts & Shortcuts

    If two objects A and B start simultaneously from opposite points and, after meeting, reach their destinations in ‘a’ and ‘b’ hours respectively (i.e. A takes ‘a hrs’ to travel from the meeting point to his destination and B takes ‘b hrs’ to travel from the meeting point to his destination), then the ratio of their speeds is given by:
    Sa/Sb = √(b/a)

    i.e. Ratio of speeds is given by the square root of the inverse ratio of time taken.

    Two trains A and B starting from two points and travelling in opposite directions, reach their destinations 9 hours and 4 hours respectively after meeting each other. If the train A travels at 80kmph, find the rate at which the train B runs.

    Sa/Sb = √(4/9) = 2/3
    This gives us that the ratio of the speed of A : speed of B as 2 : 3.
    Since speed of A is 80 kmph, speed of B must be 80 * (3/2) = 120 kmph

    A and B start from Opladen and Cologne respectively at the same time and travel towards each other at constant speeds along the same route. After meeting at a point between Opladen and Cologne, A and B proceed to their destinations of Cologne and Opladen respectively. A reaches Cologne 40 minutes after the two meet and B reaches Opladen 90 minutes after their meeting. How long did A take to cover the distance between Opladen and Cologne?

    Sa/Sb = sqrt(90/40) = 3/2

    This gives us that the ratio of the speed of A : speed of B as 3:2. We know that time taken is inversely proportional to speed. If ratio of speed of A and B is 3:2, the time taken to travel the same distance will be in the ratio 2:3. Therefore, since B takes 90 mins to travel from the meeting point to Opladen, A must have taken 60 (= 90*2/3) mins to travel from Opladen to the meeting point

    So time taken by A to travel from Opladen to Cologne must be 60 + 40 mins = 1 hr 40 mins

    [Credits: Veritasprep]

    posted in Quant Primer
  • RE: Discussion Room : Quant

    @vinaycat2017
    Let the total distance be d
    truck started it journey with 100 kmph and continued so for distance d/3
    At d/3 it unloaded 150 cartons, so speed is increased by 20 + 20 + 400/100 = 44% (using successive percentage change formula)
    So d/3 distance covered at 100 kmph
    next d/3 distance covered at 144 kmph
    and last d/3 distance covered at 172 kmph
    average speed = 3abc/(ab + bc + ca) = 132 (approx)
    d = 132 * 9.82 = 1296 km (approx)

    posted in Discussion Room

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