@swati-jha Thanks Swati. Corrected the solution.
Mistake was in distance values and is now clean, hopefully :)
Happy learning!
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RE: Question Bank - 100 Arithmetic Questions From Previous CAT Papers (Solved)
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RE: Question Bank - 100 Algebra Questions From Previous CAT Papers (Solved)
No one is perfect here yaar and if you find a mistake in a solution and know the right answer, least thing to do is to share the solution. That's how a forum (should) function right ? :)
Corrected the question. -
RE: Quant Boosters - Hemant Malhotra - Set 14
Q30) A teacher asks one of her students to divide a 30-digit number by 11. The number consists of six consecutive 1’s, then six consecutive 2’s, and likewise six 3’s, six 4’s and six 7’s in that order from left to right. The student inserts a three-digit number between the last 4 and the first 7 by mistake and finds the resulting number to be divisible by 11. Find the number of possible values of the three-digit number.
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RE: Quant Boosters - Hemant Malhotra - Set 14
let A,B,C,D
let A got a rs
B got a * b rupees
C got a * b * c rupees
D got a * b * c * d rupees
a(1+b+bc+bcd)=70
a * (1+b+bc+bcd) = 2 * 35
this will be minimum when all values are as close as possible
1+b+bc+bcd=35
b(1+c+cd)=34
so b=2
1+c+cd=17
so c(1+d)=16
so c=4 and d=3
so a=2,b=2,c=4,d=3
so 2,4,16,48 these are values -
RE: Quant Boosters - Hemant Malhotra - Set 14
Q29) In a group of four boys, each of them has a certain number of Re. 1 coins with him. Every boy has an amount that is an integral multiple of the amount possessed by every other boy who has an amount less than him. If the total amount with the four boys put together is Rs. 70, and no two boys have the same amount, what is the minimum possible amount (in Rs.) with the boy who has the maximum number of Rs. 1 coins with him?
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RE: Quant Boosters - Hemant Malhotra - Set 14
Q28) How many arrangements can be made in a round table of 8 chairs if 2 of them like to sit opposite to each other ?
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RE: Quant Boosters - Hemant Malhotra - Set 14
1step = 1 way =2^0
2 step = (1,1) , (2,0) = 2^1 way
3 step = (1,1,1) , (2,1) ,(1,2) ,(3)=2^2=4 way
4 step = 2^3= 8 way
5 step = 2^4 = 16 way
6 step = 2^5 = 32 way
now step 7th step will be sum of previous 6 steps= 63
8th step = sum of previous 6 step = 125 -
RE: Quant Boosters - Hemant Malhotra - Set 14
Q27) In how many ways can you climb up 8 steps if the minimum and maximum steps you can take at a time are 1 and 6 respectively?
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RE: Question Bank - 100 CAT level questions on Time, Speed and Distance topic
t + t/12 = 9 (time taken in the return journey is 1/12th the time taken for the onward journey)
t = 108/13 = 8.30 hours
t + t/6 = 9.68 hours? -
RE: Quant Boosters - Hemant Malhotra - Set 14
Q26) A teacher asks one of her students to divide a 30-digit number by 11. The number consists of six consecutive 1’s, then six consecutive 2’s, and likewise six 3’s, six 4’s and six 7’s in that order from left to right. The student inserts a three-digit number between the last 4 and the first 7 by mistake and finds the resulting number to be divisible by 11. Find the number of possible values of the three-digit number