@YashHChaudhari Could you please provide your solution?

RE: Quant Boosters  Hemant Malhotra  Set 14

RE: Question Bank  100 Arithmetic Questions From Previous CAT Papers (Solved)
@swatijha Thanks Swati. Corrected the solution.
Mistake was in distance values and is now clean, hopefully :)
Happy learning! 
RE: Discussion Room : Quant
@rohitchopra01 said in Discussion Room : Quant:
If 76/(4+√7+√11)=p+q√7+r√11+s√77 then p+q+r+s=?
Multiply both sides by (4 + 71/2 + 111/2)
76 = (4 + 71/2 + 111/2)p + 71/2(4 + 71/2 + 111/2)q + 111/2(4 + 71/2 + 111/2)r + 771/2(4 + 71/2 + 111/2)s
Expand out:
76 = 4p + 71/2p + 111/2p + 71/24q + 7q + 771/2q + 111/24r + 771/2r + 11r + 771/24s + 111/27s + 71/211sNow get everything together:
76 = (4p+7q+11r) + 71/2(p+4q+11s) + 111/2(p+4r+7s) + 771/2(q+r+4s)Rewrite the LHS:
76 + 0 * 71/2 + 0 * 111/2 + 0 * 771/2 = (4p+7q+11r) + 71/2(p+4q+11s) + 111/2(p+4r+7s) + 771/2(q+r+4s)So we have the following system of equations:
4p + 7q + 11r = 76
p + 4q + 11s = 0
p + 4r + 7s = 0
q + r + 4s = 04 equations in 4 unknowns. Solve.

RE: Discussion Room : Quant
@swanandk12 I think it is infinity. As x increases the value of F(x) will keep on increasing. So possible values of F(x) are infinite. Hence the sum of possible values F(x) is infinity. Thoughts?

RE: Question Bank  100 Algebra Questions From Previous CAT Papers (Solved)
No one is perfect here yaar and if you find a mistake in a solution and know the right answer, least thing to do is to share the solution. That's how a forum (should) function right ? :)
Corrected the question. 
RE: Question Bank  100 CAT level questions on Time, Speed and Distance topic
t + t/12 = 9 (time taken in the return journey is 1/12th the time taken for the onward journey)
t = 108/13 = 8.30 hours
t + t/6 = 9.68 hours? 
RE: Question Bank  Algebra  Shashank Prabhu, CAT 100 Percentiler
@shreyasnegi13
There are 10 primes in the given range.
4 also satisfies
9 and 25 won't work because we would already have two 3s and 5s respectively in the numerator
So 10 + 1 = 11 values. 
RE: Discussion Room : DILR
120 = I + II + III (Where I  number of students who attended exactly one interview, II  exactly two interviews and III  exactly three interviews)
I > II > III
III is atleast 1a) maximum number of students who attended exactly 3 companies.
We have to minimize I and II.
Let say x people attended all three. and let x + 1 attended exactly two companies and x + 2 attended exactly one company.
So 3x + 3 = 120
x = 39 
RE: Discussion Room : Quant
120 rupees is the original price
25 rupees down payment means 95 rupees is what we are "Borrowing" from the shop.
Amount paid in instalments = 25 * 4 = 100
So 100  95 = 5 is the interest
Now this interest gained (Rs 5) is through the interest gained in the available amount month by month.
5 = 95R/(12 * 100) + 70R/(12 * 100) + 45R/(12 * 100) + 20R/(12 * 100)
5 = 230R/(12 * 100)
R = 6000/230 = 26.09%