@gaurav_sharma said in Quant Boosters - Gaurav Sharma - Set 5:
Q26) John and David work on alternate days with John starting on the first day. John does 12.5% of the total work on the last day and finishes the work. If John alone can do the work in 6 days then which of following can be the number of days in which David alone can do the whole work?(a) 24 days(b) 12 days(c) 8 days(d) 10 days
Need solutioninlinemathsinline mathsinlinemaths
@Rowdy-Rathore
F(x) = x^4-360x^2+400F(x) = (x^2+20)^2 - 400x^2F(x) = (x^2-20x+20)(x^2+20x+20) = Prime NumberSince the value of second factor is always positive and greater than 1 therefore, 1st factor hasto be equals to 1.x^2-20x+20 = 1x^2-20x+19= 0On solving,x = 1, 19.Putting back the values in the original equation we get f(x) = 41 and f(x) = 761.
So, the sum will be 41+761 = 802
@rajesh_balasubramanian Hello. I was just looking for an online CAT coaching and stumbled upon this. The answer seems to be 7. And i don't think 10 can be a value for B. Eg: Take the Track length as 300m. A will complete it in 50secs. And B will take 75 secs to overlap A for the first time(300/4). I can email you my solution if you'd like to give it a look.
Thank you.
@raman_sharma
BC =1 , CA =2 so AB =rt5using similarity in triangle ABC and ADCwe get CD= 2/rt5 and diameter of circle as 4/rt5
now using tangent secant theoremCD^2 = CE * AC4/5 = CE *2CE =0.4so AE=1.6hence 1.6/0.4 = 4
@vikas_saini can u plz explain 2nd and 3rd+4th step again. 2nd step:what is -1-what are we reducing in it
3rd step: 3rd+4th step doesnt giv value in 2nd step. what are we missing in it. 3rd+4th= 2T-2
