@mbatious
At the time of meeting,
Let the distance travelled by first train be X
Let the distance travelled by second train be x+60
Given,
Speed of fist train = 16km/hr
Speed of second train =21km/hr
Since they begin at the same time and meet each other,
x/16=(x+60)/21
~x=192 km
Total Distance= x+60+x
=444km
@zabeer x=8 the value turns out to be 108 u should always look for a no which can create max difference between the give nos like (8 and 6) and (11 and 8)
